-2x^2+2400x=0

Solution for -2x^2+2400x=0 equation:

-2x^2+2400x=0

a = -2; b = 2400; c = 0;
Δ = b2-4ac
Δ = 24002-4·(-2)·0
Δ = 5760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5760000}=2400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-2400}{2*-2}=\frac{-4800}{-4}
=+1200
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+2400}{2*-2}=\frac{0}{-4}
=0
$